Two concentric circles are of radii a and b (a>b). Length of the chord of the larger circle which touches the small circle is

(A) \(2\sqrt{a^2-b^2}\)

(B) \(\sqrt{a^2-b^2}\)

(C) \(2\sqrt{a^2+b^2}\)

(D) \(\sqrt{a^2+b^2}\)

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1 Answers

Correct option is: (A) \(2\sqrt{a^2-b^2}\)

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