In a ΔXYZ, if the internal bisector of ∠X meets YZ in P. Then (A) XY/XZ = YP/PZ (B) XY/PZ = XZ/YP

In a ΔXYZ, if the internal bisector of ∠X meets YZ in P. Then

(A) XY/XZ = YP/PZ

(B) XY/PZ = XZ/YP

(C) XY/XZ = PZ/XP

(D) XZ/XY = YZ/YP

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct option is: (A) \(\frac{XY}{XZ}=\frac{YP}{PZ}\)

4 views Answered 2023-02-05 15:29

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