A wire of resistance `4 Omega` is used to wind a coil of radius 7 cm. The wire has a diameter of 1.4 mm and the specific resistance of its material is

Question

A wire of resistance `4 Omega` is used to wind a coil of radius 7 cm. The wire has a diameter of 1.4 mm and the specific resistance of its material is

A wire of resistance `4 Omega` is used to wind a coil of radius 7 cm. The wire has a diameter of 1.4 mm and the specific resistance of its material is `2xx10^(-7) Omega m`. Find the number of turns in the coil.
A. 50
B. 40
C. 60
D. 70

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

The resistance of a wire is `2 Omega`. The wire is stretched to doubel its length. Now the resistance of the wire will become

2 Answers 5 Views

The wire of potentiometer has resistance `4 Omega` and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance `1 Omega`. The curren

2 Answers 4 Views

A plantinum wire has resistance of `10 Omega` at `0^(@)C` and `20 Omega` at `273^(@)C`. Find the value of coefficient of resistance.

2 Answers 4 Views

the length of wire of diameter 0.5 mm needed to produce a coil of resistance `10Omega` and specific resistance `4.4xx10^(-7)Omega` m is

2 Answers 4 Views

The resistance of a wire of length 40 m and radius o.25 mm is `10 Omega`. The conductivity of the material of the wire is

2 Answers 4 Views

The valules of resistance and inductive reactance of a choke coil are `8 Omega` and `6 Omega` respectively. What is the power factor of the coil?

2 Answers 5 Views

50 turns of a wire of diameter 1mm is wound on a cylinder of radius 5 cm. If the specific resistance of the materical of the wire is `4.5xx10^-6Omegam

2 Answers 4 Views

The voltage over a cycle varies as `V=V_(0)sin omega t` for `0 le t le (pi)/(omega)` `=-V_(0)sin omega t` for `(pi)/(omega)le t le (2pi)/(omega)` The

2 Answers 11 Views

A coil of resistance 100 `Omega` having 100 turns is placed in a magnetic field. A galvanometer of resistance `400 Omega` is connected in series with

2 Answers 9 Views

If the length of wire is `(100.0 cm) and radius of wire as measured from screw gauge is (1.00mm) then the specific resistance of wire material is .

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Let n be the number of turns in the coil.
Then the total length of wire used. `l=2pir xx n=2pixx7xx10^(-2)xxn`
Total resistance, `R=rho(l)/(A)`
or `4=(2xx10^(7)xx2pixx7xx10^(-2)xxn)/(pi(0.7xx10^(-3))^(2))therefore n=70`

4 views Answered 2023-02-05 15:29