Two solutions of a substance (non-electrolyte) are mixed in the following manner. `480 mL` of `1.5M` first solution `+520 mL` of `1.2M` second solutio

Question

Two solutions of a substance (non-electrolyte) are mixed in the following manner. `480 mL` of `1.5M` first solution `+520 mL` of `1.2M` second solutio

Two solutions of a substance (non-electrolyte) are mixed in the following manner. `480 mL` of `1.5M` first solution `+520 mL` of `1.2M` second solution. What is the molarity of the final mixture?
A. `1.20M`
B. `1.50M`
C. `1.344 M`
D. `2.70M`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`underset(("1st sol"))(M_(1)V_(1)) + underset(("2nd sol"))(M_(2)V_(2)) = underset(("Mixture"))(M_(3)V_(3))`
`1.5xx480+1.2xx520=M_(3)(480+520)`
`1.5xx480+1.2xx520=M_(3)(480+520)`
`1000 M_(3) = 720+ 624`
`M_(3) = (1344)/(1000)=1.344 M`

4 views Answered 2023-02-05 15:29