An inductor 20mH, a capacitor `100muF` and a resistor `50Omega` are connected in series across a source of emf V=10sin314t. The power loss in the circ

Question

An inductor 20mH, a capacitor `100muF` and a resistor `50Omega` are connected in series across a source of emf V=10sin314t. The power loss in the circ

An inductor 20mH, a capacitor `100muF` and a resistor `50Omega` are connected in series across a source of emf V=10sin314t. The power loss in the circuit is
A. 2.74 W
B. 0.43 W
C. 0.79 W
D. 1.13 W

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`Z=sqrt(R^2+(omegaL-1/(omegaC))^2)`
`=sqrt((50)^2+[314times20times10^-3-1/(314times100times10^-6)]^2)`
`=56.16Omega`
The power loss in the circuit,
`P=(V_(rms)/Z)^2.R=((10/sqrt2)/56.16)^2times50=0.79W`

4 views Answered 2023-02-05 15:29