The number of iodine atoms present in 40mL solution of its 0.1M solution is
The number of iodine atoms present in 40mL solution of its 0.1M solution is
A. `4.81 xx 10^(21)`
B. `24.08 xx 10^(21)`
C. `0.408 xx 10^(23)`
D. `6.02 xx 10^(22)`
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Correct Answer - A
Iodine atoms `= 2 xx N xx (40 xx 10^(-3) xx 0.1)`
`= 2xx 6.02 xx 10^(23) x 40 xx 10^(4)`
`= 4.81 xx 10^(21)`
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