The number of iodine atoms (N) present in `1 "cm"^(3)` of its 0.1 M solution is

Question

The number of iodine atoms (N) present in `1 "cm"^(3)` of its 0.1 M solution is

The number of iodine atoms (N) present in `1 "cm"^(3)` of its 0.1 M solution is
A. `6.02 xx 10^(23)`
B. `6.02 xx 10^(2)`
C. `6.02 xx 10^(19)`
D. `1.204 xx 10^(20)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
1 cc of 0.1 M `I_(2)` sol. `=0.1/1000=10^(-4)` mol
`N = n xx N_(A)`
`=10^(-4) xx 6.02 xx 10^(23)` molecules
`=6.02 xx 10^(19)` molecules
`=2 xx 6.02 xx 10^(19)` atoms `=1.204 xx 10^(20)`

4 views Answered 2023-02-05 15:29