The limmiting molar conductivites `^^ ^(@)` for `NaCl_(2) ` Kbr and KCl are 126,152 and 150 S `cm^(2)` respectively the `^^ ^(@)` for NaBr is

Question

The limmiting molar conductivites `^^ ^(@)` for `NaCl_(2) ` Kbr and KCl are 126,152 and 150 S `cm^(2)` respectively the `^^ ^(@)` for NaBr is

The limmiting molar conductivites `^^ ^(@)` for `NaCl_(2) ` Kbr and KCl are 126,152 and 150 S `cm^(2)` respectively the `^^ ^(@)` for NaBr is
A. `128Scm^(2)"mol"^(-1)`
B. `302Scm^(2)"mol"^(-1)`
C. `278S cm^(2)"mol"^(-1)`
D. `176Scm^(2)"mol"^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`^^_(NaBr)^(@)=^^_(NaCl)^(@)+^^_(KBr)^(@)-^^_(KCl)^(@)`
`=126+152-150=128 S cm^(2)"mol"^(-1)`

4 views Answered 2023-02-05 15:29