96500C electricity is passed through `CuSO_(4)` the amount of copper precipitated is
96500C electricity is passed through `CuSO_(4)` the amount of copper precipitated is
A. 0.25 mole
B. 0.5mole
C. 1.0mole
D. 2.00mole
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Correct Answer - B
`underset(1"mole")(Cu^(2+))+underset(2"Faraday"=2xx96500C)(2e^(-))rarrCu`
2xx96500C deposits 1 mole of copper
96500C deposits 0.5 mole of copper.
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