The EMF of the following cell is 0.86 volts `Ag|AgNO_(3)(0.0093M)||AgNO_(3)(xM)|Ag`. The value of x will be
The EMF of the following cell is 0.86 volts `Ag|AgNO_(3)(0.0093M)||AgNO_(3)(xM)|Ag`. The value of x will be
A. 82.8M
B. 2.28M
C. 0.228M
D. 1.14M
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Correct Answer - C
`E=(0.059)/(1)"log"(C_(2))/(C_(1))`
`0.086=(0.059)/(1)"log"(x)/(0.0093)`
`x=0.228M`
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