A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper lib erated from a solution `CuSO_(4)` by the same current flowing for the same time would be
A. 31.8g
B. 63.6g
C. 15.9g
D. 6.36g

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1 Answers

Correct Answer - A
g eq. of hydrogen =g eq. of Cu
`(0.504)/(1)=(W)/(63.5//2) therefore W=15.9g`

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