The addition of HCl in propene proceeds via
The addition of HCl in propene proceeds via
A. `Cl^(+)` in first stpe
B. `H^(+)` in first step
C. `H^(-)` in first step
D. `Cl^(+) and H^(+)` in single step
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Correct Answer - B
Since oxygen is more electronegative than cl, therefore, heterolytic of HO-Cl gives `HO^(-) and Cl^(+)`. Since alkene undergoes `E^(+) AR,` therefore the electrophilic `Cl^(+)` attack first to generate more stable carboncation, which then undergoes mcleophilic attack by `OH^(-)` to give propylene chlorohydrine
`CH_(3)-CH=CH_(2)+Cl^(+) to CH_(3)- overset(o+)(CH)-CH_(2)Cl`
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