The inversion of cane sugar is first order in [sugar] and proceeds with half-life of 600 min at pH=4 for a given concentration of sugar. However , if
The inversion of cane sugar is first order in [sugar] and proceeds with half-life of 600 min at pH=4 for a given concentration of sugar. However , if pH=5, the half-life changes to 60 min. The rate law expression for the sugar inversion can be written as
A. `rate=k[sugar]^(1)[H^+]^(2)`
B. `rate=k[sugar][H^(+)]^(1)`
C. `rate=k[sugar][H^(+)]^(4)`
D. `rate=k[sugar][H^(+)]^(0)`
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Correct Answer - D
`"Rate"=k[A]^(a)[B]^(b)`
Overall order of reaction = a+b
Inversion of cane sugar is first order reaction (given).
Hence, `"rate"=k[sugar]^(a)[H^(+)]^(b)anda+b=1`
In the given options, only (d) has value of a+b=1
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