Light of wavelength `lambda` falls on metal having work functions `hc//lambda_(0)` . Photoelectric effect will take place only if :
Light of wavelength `lambda` falls on metal having work functions `hc//lambda_(0)` . Photoelectric effect will take place only if :
A. `lamdagelamda_(0)`
B. `lamdalelamda_(0)`
C. `lamdage2lamda_(0)`
D. `lamda=4lamda_(0)`
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Correct Answer - B
(b) : As kinetic energy `K=(hc)/(lamda)-(hc)/(lamda_(0))`
K is positive therefore photoelectric emission will take place if `K=(hc)/(lamda)ge(hc)/(lamda_(0)) or lamdalelamda_(0)`
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