Four resistances of `3Omega, 3Omega, 3Omega and 4Omega` respectively are used to form a Wheatstone bridge. The `4Omega` resistance is short circuited
Four resistances of `3Omega, 3Omega, 3Omega and 4Omega` respectively are used to form a Wheatstone bridge. The `4Omega` resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be
A. `10Omega`
B. `11Omega`
C. `12Omega`
D. `13Omega`
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Correct Answer - C
The bridge will be balanced when the shunted resistance is of the value of `3Omega`
`therefore 3=(4xxR)/(4+R) ,12+3=4R, therefore R=12Omega`
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