The number of electrons passing per second through a cross-section of copper wire carrying `10^(-6)` ampere:

Question

The number of electrons passing per second through a cross-section of copper wire carrying `10^(-6)` ampere:

The number of electrons passing per second through a cross-section of copper wire carrying `10^(-6)` ampere:
A. `1. 6 xx 10^(-19)`
B. `6 xx 10^(-35)`
C. `6 xx 10^(-16)`
D. `6 xx 10^(12)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Charge flowing per sec = `10^(-6)` C .
Charge on `1 e^(-) = 1.602 xx 10^(-19) C`.
Hence , no of `e^(-)` flowing per sec
`= 10^(-6) // (1.602 xx 10^(-19)) = 6 xx 10^(12)`

4 views Answered 2023-02-05 15:29