When calomel electrode acts as an anode then the reaction is
A. `2 Hg + 2 Cl^(-) to Hg_(2) Cl_(2) + 2e^(-)`
B. `Hg_(2) Cl_(2) to 2 Hg^(+) + Cl_(2) + 2e^(-)`
C. `Hg_(2) Cl_(2) + 2e ^(-) to 2 Hg + Cl_(2)`
D. `Hg_(2) Cl_(2) + 2e^(-) to 2 Hg + 2 Cl^(-)`

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1 Answers

Correct Answer - A
The cell reactions are at anode (oxidation)
`2 Hg + 2 Cl^(-) to Hg_(2) Cl_(2) + 2 e^(-)`

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