6g of urea is dissolved in 90g of water. The relative lowering of vapour pressure is equal to
6g of urea is dissolved in 90g of water. The relative lowering of vapour pressure is equal to
A. 0.0196
B. 0.5
C. 0.1
D. 0.0202
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Correct Answer - A
`(P_(1)^(o)-P)/P_(1)^(o)=("Mass of solute/molar mass")/("Mass of soute"/"Molar mass"+"Mass of solvent"/"Molar Mass")`
`(6//60)/(6/60+90/18)=(1//10)/(1/10+5/1)=1/51=0.0196`
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