`N_(2)` exerts a pressure of 0.987 bar. The mole fraction of `N_(2)` ia `(K_(H)=74.48 k `bar)
`N_(2)` exerts a pressure of 0.987 bar. The mole fraction of `N_(2)` ia `(K_(H)=74.48 k `bar)
A. `7.648 xx 10^(-3)`
B. `9.87 xx 10^(-5)`
C. `1.3 xx 10^(-5)`
D. `2.6 xx 10^(-5)`
4 views
1 Answers
Correct Answer - C
`P_(N2)=K_(H) xx X_(N2)`
`:. X_(N2)=P_(N2)/K_(H)=(0.987"barr")/(76480"bar")=1.29 xx 10^(-5)`
4 views
Answered