A 0.6% solution of urea (molecular mass =60) would be isotonic with
A. 0.1 M glucose
B. 0.1 M KCl
C. 0.6% glucose
D. 0.6 % KCI

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1 Answers

Correct Answer - A
0.6% urea `sol^(n)=0.6/60 xx 1/100 xx 1000 = 0.1 M.`

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