The reverse currents corresponding to reverse voltages 10 V and 20 V are `25 muA` and 50 muA ` respectively . The reverse resistance is
A. `40k Omega`
B. `40k Omega`
C. `400k Omega`
D. `4mu Omega`

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1 Answers

Correct Answer - C
`r_(r)=(deltaV)/(deltaI)=(20-10)/((50-25)xx10^(-6))=400xx10^(3) Omega`

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