Two capacitors having capacities `C_(1) and C_(2)` are charged to voltages `V_(1) and V_(2)` respectively. There will be no exchange of energy in conn
Two capacitors having capacities `C_(1) and C_(2)` are charged to voltages `V_(1) and V_(2)` respectively. There will be no exchange of energy in connecting them in parallel, if
A. `C_(1)=C_(2)`
B. `C_(1)V_(1)=C_(2)V_(2)`
C. `V_(1)=V_(2)`
D. `(C_(1)V_(1))/(C_(2)V_(2))`
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Correct Answer - C
Loss of energy = `1/2((C_(1)C_(2))/(C_(1)+C_(2)))(V_(1)-V_(2))^(2)`
If `V_(1) = V_(2)`, loss of energy = 0
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