A metal rod of length 0.5 m rotates at a uniform angular speed about one of its ends in a plane at right angle to a uniform magnetic field of induction `10^(-5)T`. If it turns through an angle of `60^(@)` ini 0.1 s. then the emf induced between its ends will be
A. 13 `muV`
B. 31 `muV`
C. 15 `muV`
D. 20 `muV`

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1 Answers

Correct Answer - A
`theta=omegat=2pift`
`therefore f=(theta)/(2pit)`
`=(pi)/(3xx2pixx0.1)=(1)/(0.6)`
`=(10^(-5)xxpixx0.25xx1)/(0.6)=13muV`

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