A thin rod of length L is magnetised and has magnetic moment M.The rod is then bent in a semicircular arc.The magnetic moment in the new shape is
A thin rod of length L is magnetised and has magnetic moment M.The rod is then bent in a semicircular arc.The magnetic moment in the new shape is
A. `(M)/(L)`
B. `(M)/(pi)`
C. `(M)/(2pi)`
D. `(2M)/(pi)`
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Correct Answer - D
Radius=r,`therefore l=pi r therefore r=(1)/(pi)`
Distance between two poles`=2r(2l)/(pi)`,
pole strength `=m=(M)/(l)`
Thus,magnetic moment`=(M)/(l) (2l)/(pi) =(2M)/(pi)`
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