An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be
An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be
A. 4M
B. M/4
C. `2M//pi`
D. 2M
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Correct Answer - C
Radius=r,`therefore l=pir therefore r=(1)/(pi)`
Distance between two poles`=2r=(2l)/(pi)`
Pole strength `=m=(M)/(l)`
Thus,magnetic moment`=(M)/(l)(2l)/(pi)=(2M)/(pi)`
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