A coil of cross sectional area 100 `cm^(2)` is placed in the magnetic field, which changes to `4xx10^(-2)Wb//cm^(2)` within 5s. What will be the curre

Question

A coil of cross sectional area 100 `cm^(2)` is placed in the magnetic field, which changes to `4xx10^(-2)Wb//cm^(2)` within 5s. What will be the curre

A coil of cross sectional area 100 `cm^(2)` is placed in the magnetic field, which changes to `4xx10^(-2)Wb//cm^(2)` within 5s. What will be the current across `5Omega` resistance?
A. 0.016 A
B. 0.16 A
C. 1.6 A
D. 16.0 A

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`e=A(dB)/(dt)`
`=(100xx10^(-4)xx4xx10^(2))/(5)=0.8V`
`I=(e)/(R)=(0.8)/(5)=0.16A`

4 views Answered 2023-02-05 15:29