A magnetising field of `2xx10^(3)Am^(-1)` produces a magnetic flux density of `8piT` in an iron rod. The relative permeability of the rod will be
A magnetising field of `2xx10^(3)Am^(-1)` produces a magnetic flux density of `8piT` in an iron rod. The relative permeability of the rod will be
A. `10^(2)`
B. `10^(0)`
C. `10^(3)`
D. `10^(4)`
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Correct Answer - D
`mu_(r)=(mu)/(mu_(0))=(B)/(mu_(0)H)`
`=(8pi)/((4pixx10^(-7))(2xx10^(3)))`
`mu_(r)=10^(4)`
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