A cyclotron is operating at a frquency of `12xx10^6Hz`. Mass of deutron is `3.3 xx10^-19` coulomb. To accelerate deutrons the magnetic field is
A cyclotron is operating at a frquency of `12xx10^6Hz`. Mass of deutron is `3.3 xx10^-19` coulomb. To accelerate deutrons the magnetic field is
A. 0.016 tesla
B. 0.16 tesla
C. 16 tesla
D. 1.6 tesla
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Correct Answer - D
`v =(q B)/(2 pi m)`
`therefore B =(2 pi mv )/(q)`
`=(2xx3.14xx3.3 xx10^-27xx12xx10^6)/(1.6xx10^-19)`
`= 1.6 T`.
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