If length of a conductor is doubled by keeping volume constant, then what is its new resistance if initial were `4Omega` ?

Question

If length of a conductor is doubled by keeping volume constant, then what is its new resistance if initial were `4Omega` ?

If length of a conductor is doubled by keeping volume constant, then what is its new resistance if initial were `4Omega` ?
A. `16Omega`
B. `8Omega`
C. `4Omega`
D. `2Omega`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`R_(1)=4 Omega, R_(2)=? ` if `l_(2)=2l_(1)` by keeping volume constant.
`(R_(2))/(R_(1))=((l_(2))/(l_(1)))^(2)`
`R_(2)=((2l_(1))/(l_(1)))^(2) R_(1)=4xx4=16 Omega`.

4 views Answered 2023-02-05 15:29