Two capacitor each of capacity `4muF` are connected in series and third capacitor of capacity `4muF` is connected in parallel with the combination. Th

Question

Two capacitor each of capacity `4muF` are connected in series and third capacitor of capacity `4muF` is connected in parallel with the combination. Th

Two capacitor each of capacity `4muF` are connected in series and third capacitor of capacity `4muF` is connected in parallel with the combination. The equivalent capacitance of the arrangement is
A. `12muF`
B. `8muF`
C. `6muF`
D. `2.65muF`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`C_(1)=C_(2)=4muF,C_(3)=4muF,C_(P)=?`
`C_(s)=(C_(1)*C_(2))/((C_(1)+C_(2)))=(4xx4)/(4+4)=2muF`
Now`" "C_(S) and C_(3)` are in parallel
`therefore" "C_(P)=C_(S)+C_(3)=2+4=6muF`

5 views Answered 2023-02-05 15:29