The surface charge density of a conducting sphere is `8.85xx10^(-10)C//m^(2)` and the electric field intensity at a distance of 4m from the centre of

Question

The surface charge density of a conducting sphere is `8.85xx10^(-10)C//m^(2)` and the electric field intensity at a distance of 4m from the centre of

The surface charge density of a conducting sphere is `8.85xx10^(-10)C//m^(2)` and the electric field intensity at a distance of 4m from the centre of the sphere is `10^(-2)V//m`. The radius of the sphere, assuming the sphere to be in vacuum is
A. 3 cm
B. 4 mm
C. 4 cm
D. 4 km

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`E=(sigmaR^(2))/(epsi_(0)kr^(2))`
`therefore" "R^(2)=(Eepsi_(0)kr^(2))/sigma=(10^(-2)xx8.85xx10^(-12)xx1xx16)/(8.85xx10^(-10))`
R = 4 cm

4 views Answered 2023-02-05 15:29