In a biprism experiment, fringe width is `0.4` mm when the eypiece is at a distance of 1 mm from the slit. If eyepiece is moved without changing any other arrangment then the change in fringe width is
A. `0.1 mm `
B. `0.2 mm`
C. `0.15 mm`
D. `0.25mm`

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1 Answers

Correct Answer - A
`beta_(2)=(D_(2))/(D_(2)) beta_(1)=(0.75xx0.4xx10^(-3))/(1) 0.3 mm`
Thus, change in fring width is,
`beta_(1)-beta_(2)=0.4-0.3=0.1 mm`

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