If the electron in hydrogen atom jumps from second Bohr orbit to ground state and difference between energies of the two states is radiated in the for

Question

If the electron in hydrogen atom jumps from second Bohr orbit to ground state and difference between energies of the two states is radiated in the for

If the electron in hydrogen atom jumps from second Bohr orbit to ground state and difference between energies of the two states is radiated in the form of photons. If the work function of the material is `4.2 eV`, then stopping potential is
[Energy of electron in nth orbit `= - (13.6)/(n^(2)) eV`]
A. 2eV
B. 4eV
C. 6eV
D. 8eV

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`E=(13.6)/(1)-(13.6)/(2^(2))`
`E=13.6 [(4-1)/(4)]=13.6 xx 3/4`
`thererfore E=10.2eV (=hv)`
i.e, `hv=10.2eV`
`hv=phi_(0)+eV_(S)`
`therefore 6eV=eV_(s)`
`therefore V_(s)=6V`

4 views Answered 2023-02-05 15:29