The maximum energy in thermal radiation from a source occurs at the wavelength 4000Å. The effective temperature of the source
The maximum energy in thermal radiation from a source occurs at the wavelength 4000Å. The effective temperature of the source
A. 7000 K
B. 80000 K
C. `10^(4)K`
D. `10^(6)K`
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Correct Answer - A
`lamda_(m)=(b)/(T) " "therefore T=(b)/(lamda_(m))=(2.93xx10^(-3))/(4000xx10^(-10))=7325K`.
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