The efficiency of a Carnot engine operating between temperatures of `100^(@)C` and `-23^(@)C` will be
A. `(100-23)/(100)`
B. `(100-23)/(373)`
C. `(100+23)/(373)`
D. `(100+23)/(100)`

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1 Answers

Correct Answer - C
`eta=(T_(1)-T_(2))/(T_(1))=((273+100)-(273-23))/(273+100)=(100+23)/(373)`

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