When two gases having volumes 1 litres and 2 liters are at the same temperature, then the ratio of the average kinetic energy of the molecules in the two gases
A. `1:1`
B. `1:2`
C. `2:1`
D. `3:2`

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1 Answers

Correct Answer - A
`(KE_(1))/(KE_(2))=((3)/(2)RT)/((3)/(2)RT)=(1)/(1)`

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