A wire having a linear density of 0.05 kg/m is stretched between two rigid supports. The tension in the wire is `4.5xx10^7` dyne . If the observed tha

A wire having a linear density of 0.05 kg/m is stretched between two rigid supports. The tension in the wire is `4.5xx10^7` dyne . If the observed that the wire resonates at a frequency of 420 Hz and the next higher frequency at which the wire resonates is 490 Hz, then the length of the wire would be
A. 75 cm
B. 21.4 cm
C. 214m
D. 114m

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - C
`n=n_2-n_1 = (1)/(2l) sqrt(T/m)`
`70=(1)/(2l) sqrt((4.5xx10^7)/(0.05))`
`therefore l=(1)/(140)3xx10^4 = 214.2cm`

6 views Answered 2023-02-05 15:29

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