The phase of a particle at `P_(1) " is " 60^(@)` and the phase of a particle at `P_(2) " is " 780^(@)`. If the distance between `P_(1) and P_(2)` is 1

Question

The phase of a particle at `P_(1) " is " 60^(@)` and the phase of a particle at `P_(2) " is " 780^(@)`. If the distance between `P_(1) and P_(2)` is 1

The phase of a particle at `P_(1) " is " 60^(@)` and the phase of a particle at `P_(2) " is " 780^(@)`. If the distance between `P_(1) and P_(2)` is 1m, then the wavelength of the wave, will be
A. 2m
B. 0.5 m
C. 1.5 m
D. 0.25 m

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`delta = (2pix)/(lamda) , delta_(2) - delta_(1) = 780 - 60 = 720 = 4pi`

5 views Answered 2023-02-05 15:29