The amount of work performed to break a spherical drop of radius 1 mm into million drops of equal radius , is
A. `9xx10^(-5)`J
B. `90xx 10^(-5)`J
C. `9 xx 10^(-6)`J
D. `9 xx 10^(-7)`J

4 views

1 Answers

Correct Answer - A
` dE = 4piR^(2)T (n^(1//3)-1)`
` = 4xx3.14 xx10^(6)xx 7.2 xx10^(-2)xx99`
` = 9xx10^(-5)`J

4 views

Related Questions