A long elastic spring is stretched by 2 cm and its P.E. is 20 J. If the spring is stretched by by 10 cm, then its potential energy will be
A. 100 J
B. 250 J
C. 200 J
D. 500 J

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1 Answers

Correct Answer - D
`E_(1)=(1)/(2) K x_(1)^(2) and E_(2)=(1)/(2)K x_(2)^(2)`
`therefore E_(2)=(E_(1)x_(2)^(2))/(x_(1)^(2))`

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