Two pieces of wire, A and B of the same material have their lengths in the ratio `1:3` and their diameters are in the ratio `2:1` . If they are stretched by the same force, their elongations will be in the ratio
A. `2:1`
B. `1:6`
C. `1:12`
D. `8:1`

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1 Answers

Correct Answer - C
For constant force and same material
`=(l_(1))/(l_(2)) = (L_(1))/(L_(2))xx(r_(2)^(2))/(r_(1)^(2))=(1)/(12)`

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