The acceleration due to gravity changes from `9.8 m//s^(2)` to `9.5 m//s^(2)`. To keep the period of pendulum constant, its length must changes by

Question

The acceleration due to gravity changes from `9.8 m//s^(2)` to `9.5 m//s^(2)`. To keep the period of pendulum constant, its length must changes by

The acceleration due to gravity changes from `9.8 m//s^(2)` to `9.5 m//s^(2)`. To keep the period of pendulum constant, its length must changes by
A. 3 m
B. 0.3 m
C. 0.3 m
D. 3 cm

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`l_(1)-l_(2)=(g_(1)-g_(2))/(pi^(2))=(9.8-9.5)/(10)=(0.3)/(10)`
`=0.03m`
`=3cm`

6 views Answered 2023-02-05 15:29