The radius of a planet is `1/4` of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many

The radius of a planet is `1/4` of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface
A. `1//sqrt2`
B. `sqrt2`
C. `2sqrt2`
D. 2

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - a
`(v_(e_(2)))/(v_(e_(1)))=sqrt((g_(2)R_(2))/(g_(1)R_(1)))=sqrt((1)/(4)xx2)=(1)/(sqrt2)`.

5 views Answered 2023-02-05 15:29

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