A simple pendulum oscillating in air has a time period of `sqrt(3)`s. Now the bob of the pendulum is completely immersed in a non-viscous liquid whose
A simple pendulum oscillating in air has a time period of `sqrt(3)`s. Now the bob of the pendulum is completely immersed in a non-viscous liquid whose density is equal to `(1)/(4)`th that of the material of the bob. The new time period of simple pendulum will be
A. `sqrt(2) s`
B. `sqrt(3) s`
C. `2 s`
D. `sqrt((7)/(2)) s`
4 views
1 Answers
Correct Answer - C
`T_(N)=(T)/(sqrt(1-(d_(l))/(d_(0))))=(T)/(sqrt(1-(1)/(4)))=(2T)/(sqrt(3))=(2)/(sqrt(3))sqrt(3)`
`=2s`.
4 views
Answered