If `alpha` and `beta` denote the maximum velocity and maximum acceleration of a simple harmonic oscillator, then its amplitude of vibration is

Question

If `alpha` and `beta` denote the maximum velocity and maximum acceleration of a simple harmonic oscillator, then its amplitude of vibration is

If `alpha` and `beta` denote the maximum velocity and maximum acceleration of a simple harmonic oscillator, then its amplitude of vibration is
A. `alpha^(2)beta`
B. `beta^(2)alpha`
C. `a^(2)//beta`
D. `beta^(2)//alpha`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`(v_(m))/(a_(m))=(prop)/(beta)=(1)/(omega) thereforeomega=(beta)/(prop)`
`v_(m)=Aomega" .... (i)"`
Substitute value of `omega` in (i)
`prop=Axx(beta)/(prop)`
`therefore A=(prop^(2))/(beta)`

4 views Answered 2023-02-05 15:29