The velocity of a particle performing S.H.M. are 0.13 m/s and 0.12 m/s. When it is at 0.12 m and 0.13 m from the mean position respectively. Then the amplitude is
A. 0.117 m
B. 0.177 m
C. 11.7 m
D. 10 m

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1 Answers

Correct Answer - B
Tricks : `A=sqrt(v_(1)^(2)+v_(2)^(2))`

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