A particle executes `SHM` with an amplitude of `0.2 m`. Its displacement when its phase is `90^(@)` is
A. 0.1 m
B. 0.2 m
C. 0.4 m
D. `0.1//sqrt(2)m`

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1 Answers

Correct Answer - B
`y=Asin(omegat+phi)=0.2sin90^(@)=0.2m`

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