Moment of inertia of a ring of mass m = 3 gm and radius r = 1 cm about an axis passing through its edge and parallel to its natural axis is

Question

Moment of inertia of a ring of mass m = 3 gm and radius r = 1 cm about an axis passing through its edge and parallel to its natural axis is

Moment of inertia of a ring of mass m = 3 gm and radius r = 1 cm about an axis passing through its edge and parallel to its natural axis is
A. `10gm cm^(2)`
B. `100 gm cm^(2)`
C. `6gm cm^(2)`
D. `1gm cm^(2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`I = 2 MR^(2)=2xx3xx(1)^(2)=6 "gm cm"^(2)`.

5 views Answered 2023-02-05 15:29