Two rings of the same mass and radius are placed such that their centers are at a common point and their planes are perpendicular to each other . The moment of inertia of the system about an axis passing through the diameter of one of the rings is I . Then moment of inertia of one of the ring of the system about the central axis and perpendicular to its plane would be
A. 3I
B. `3I//2`
C. 2I
D. `2I//3`

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1 Answers

Correct Answer - A
`I=I_(1)+I_(2)`
`=MR^(2)+(MR^(2))/(2)=(3)/(2)MR^(2)=3 I`

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