A circular disc P of radius R is made from an iron plate of thickness t and another disc Q of radius 2R is made from an iron plate of thickness `(t)/(

Question

A circular disc P of radius R is made from an iron plate of thickness t and another disc Q of radius 2R is made from an iron plate of thickness `(t)/(

A circular disc P of radius R is made from an iron plate of thickness t and another disc Q of radius
2R is made from an iron plate of thickness `(t)/(2)`.
The relation between their moments of inertia `I_(p)` and `I_(Q)` about their natural axes is
A. `I_(Q)=4I_(P)`
B. `I_(P)=8I_(Q)`
C. `I_(P)=4I_(Q)`
D. `I_(Q)=8I_(P)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`I_(P)=(MR^(2))/(2)`
`(((pi R^(2))t)rho(R^(2)))/(2)=(pi t rho R^(4))/(2)`
`I_(Q)=(MR^(2))/(2)`
`=((pi(2R)^(2)(t//2))rho(2R)^(2))/(2)`
`= (pi t rho(8 R^(4)))/(2)=8I_(P)`.

4 views Answered 2023-02-05 15:29